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RFC 2108

Definitions of Managed Objects for IEEE 802.3 Repeater Devices using SMIv2

Pages: 82
Proposed Standard
Obsoletes:  1516
Part 4 of 4 – Pages 75 to 82
First   Prev   None

Top   ToC   RFC2108 - Page 75   prevText
4.  Topology Mapping

   The network mapping algorithm presented below takes information
   available from network devices such as repeaters, bridges, and
   switches, and creates a representation of the physical topology of
   the network.

   Networking devices connect to the network via one or more ports.
   Through these ports, the device is capable of hearing network packets
   sent by other devices.  By looking the source address in the packet,
   and identifying which port the packet was heard on, the device can
   provide information to a Network Management System about the location
   of an address in the network, relative to that device.  For devices
   such as bridges and switches, the association of address to port can
   be retrieved via the forwarding data base part of the Bridge MIB.
   For repeaters, the rptrAddrSearchTable may be used to perform the
   association.

   Given this information, it would be possible for the NMS to create a
   topology of the network which represents the physical relationships
   of the devices in the networks.  The following is an example of how
   this might be done:

   Assume the network:

                 =============================
                     |            |       |
                     |            |       |
                    d1           d4      d7
                   /  \          |
                  /    \         |
                d2      d3       d5
                                  |
                                  |
                                 d6

   The discovery process would first determine the existence of the
   network devices and nodes in the network.  In the above example, the
   network devices discovered would be:

                           d1,d2,d3,d4,d5,d6,d7

   From this list of discovered devices, select (arbitrarily or via some
   heuristic) a device as the starting point.  From that device,
   determine where all other devices are located in the network with
   respect to the selected device.
Top   ToC   RFC2108 - Page 76
   For example, if d1 is the selected device, the network in relation to
   d1 would look like:

                    d1
                   / | \
                  /  |  \
                d2  d3   d4,d5,d6,d7

   So d1 sees d2 on one port, d3 on another port, and d4, d5, and d6 on
   the third port.  In other words, using the rptrAddrSearchTable (if d1
   is a repeater) or the Forwarding Database (if it is a bridge or a
   switch), d1 has located d2 on one port, d1 has located d3 on another
   port, and finally, d1 has located d4, d5, d6, and d7 on yet another
   port.

   After the first step of the algorithm is accomplished, the next and
   final step is a recursive one.  Go to each of these temporary
   'segments' (e.g., the segment connecting d1 and d2, or the segment
   connecting d1 and d3, or the segment connecting d1, d4, d5, d6, and
   d7) and determine which of these devices really belongs in that
   segment.

   As new segments are created due to this process, the recursive
   algorithm visits them, and performs the exact same process.

   In the example, the segments connecting d1 and d2, and connecting d1
   and d3, require no further scrutiny, since there are only two nodes
   in those segments.  However, the segment connecting d1, d4, d5, d6,
   and d7 may prove to be one or more segments, so we will investigate
   it.

   The purpose of this step is to determine which devices are really
   connected to this segment, and which are actually connected
   downstream.  This is done by giving each of the child devices in the
   segment (d4, d5, d6, and d7) a chance to eliminate each of the others
   from the segment.

   A device eliminates another device by showing that it hears the
   parent device (in this case, d1) on one port, and the other device on
   another port (different from the port on which it heard the parent).
   If this is true, then it must mean that that device is _between_ the
   parent device and the device which is being eliminated.
Top   ToC   RFC2108 - Page 77
   In the example, we can see that device d4 can eliminate both d5 and
   d6, , but nobody can eliminate d4 and d7, because everybody hears
   them on the same port that they hear the parent device (d1).  So the
   resulting topology looks like:

                    d1
                   / | \
                  /  |  \
                d2  d3   d4,d7
                         |
                         |
                       d5,d6

   Next the algorithm visits the next segment, which is the one
   connecting d4, d5, and d6.  Using the process stated above, d5 can
   eliminate d6, since it hears d4 on a different port from where it
   hears d6.  Finally, the topology looks like:

                    d1
                   / | \
                  /  |  \
                d2  d3   d4,d7
                         |
                         |
                         d5
                         |
                         |
                         d6


   This is actually the topology shown at the beginning of the
   description.

   With this information about how the network devices are connected, it
   is a relatively simple extension to then place nodes such as
   workstations and PCs in the network.  This can be done by placing the
   node into a segment, then allowing the network devices to show that
   the node is really not part of that segment.

   This elimination can be done because the devices know what port
   connects them to the segment on which the node is temporarily placed.
   If they actually hear the node on a different port than that which
   connects the device to the segment, then the node must be downstream,
   and so it is moved onto the downstream segment.  Then that segment is
   evaluated, and so forth.  Eventually, no device can show that the
   node is connected downstream, and so it must be attached to that
   segment.
Top   ToC   RFC2108 - Page 78
   For example, assume the network:

                   =============================
                       |            |       |
                       |            |       |
                      d1           d4      d7
                     /  \          |
                    /    \         |
                  d2      d3       d5
                          |         |
                          |         |
                          e1       d6

   In this network, we are trying to place e1 where it belongs.  We
   begin by placing it arbitrarily into a segment:

                ==================================
                  |       |            |       |
                  |       |            |       |
                 e1      d1           d4      d7
                        /  \          |
                       /    \         |
                     d2      d3       d5
                                       |
                                       |
                                      d6

   In the above case, we would give d1, d4, and d7 a chance to show that
   e1 is not really on that segment.  d4 and d7 hear e1 on the same port
   which connects them to that segment, so they cannot eliminate e1 from
   the segment.  However, d1 will hear e1 on a different port, so we
   move e1 down onto the segment which is connected by that port.  This
   yields the following:

                   =============================
                       |            |       |
                       |            |       |
                      d1           d4      d7
                     /  \          |
                    /    \         |
                  d2      d3,e1    d5
                                    |
                                    |
                                   d6
Top   ToC   RFC2108 - Page 79
   Now we give everyone in that segment (besides that parent device, d1)
   a chance to eliminate e1.  Only d3 can try, and it succeeds, so we
   place e1 on segment which is connected by the port on which d3 heard
   e1.  There is no segment there (yet), so we create one, and end up
   with the following:

                   =============================
                       |            |       |
                       |            |       |
                      d1           d4      d7
                     /  \          |
                    /    \         |
                  d2      d3       d5
                          |        |
                          |         |
                          e1       d6

   which is the correct position.

5.  Acknowledgements


   This document was produced by the IETF Hub MIB Working Group, whose
   efforts were greatly advanced by the contributions of the following
   people:

               Chuck Black
               John Flick
               Jeff Johnson
               Leon Leong
               Mike Lui
               Dave Perkins
               Geoff Thompson
               Maurice Turcotte
               Paul Woodruff
Top   ToC   RFC2108 - Page 80
6.  References

   [1]  IEEE 802.3/ISO 8802-3 Information processing systems -
        Local area networks - Part 3:  Carrier sense multiple
        access with collision detection (CSMA/CD) access method
        and physical layer specifications, 1993.

   [2]  IEEE 802.3u-1995, "MAC Parameters, Physical Layer, Medium
        Attachment Units and Repeater for 100 Mb/s Operation,
        Type 100BASE-T," Sections 21 through 29, Supplement to
        IEEE Std 802.3, October 26, 1995.

   [3]  IEEE 802.3u-1995, "10 & 100 Mb/s Management," Section 30,
        Supplement to IEEE Std 802.3, October 26, 1995.

   [4]  de Graaf, K., D. Romascanu, D. McMaster, K. McCloghrie,
        and S. Roberts, "Definitions of Managed Objects for IEEE
        802.3 Medium Attachment Units (MAUs)", Work in Progress.

   [5]  McCloghrie, K., and M. Rose, Editors, "Management
        Information Base for Network Management of TCP/IP-based
        internets: MIB-II", STD 17, RFC 1213, Hughes LAN Systems,
        Performance Systems International, March 1991.

   [6]  SNMPv2 Working Group, J. Case, K. McCloghrie, M. Rose,
        and S. Waldbusser, "Structure of Management Information
        for version 2 of the Simple Network Management Protocol
        (SNMPv2)", RFC 1902, January 1996.

   [7]  SNMPv2 Working Group, J. Case, K. McCloghrie, M. Rose,
        and S. Waldbusser, "Textual Conventions for version 2 of
        the Simple Network Management Protocol (SNMPv2)", RFC
        1903, January 1996.

   [8]  SNMPv2 Working Group, J. Case, K. McCloghrie, M. Rose,
        and S. Waldbusser, "Conformance Statements for version 2
        of the Simple Network Management Protocol (SNMPv2)", RFC
        1904, January 1996.

   [9]  SNMPv2 Working Group, J. Case, K. McCloghrie, M. Rose,
        and S. Waldbusser, "Protocol Operations for version 2 of
        the Simple Network Management Protocol (SNMPv2)", RFC
        1905, January 1996.
Top   ToC   RFC2108 - Page 81
   [10] Case, J., M. Fedor, M. Schoffstall, and J. Davin, "Simple
        Network Management Protocol", STD 15, RFC 1157, SNMP
        Research, Performance Systems International, MIT Laboratory
        for Computer Science, May 1990.

   [11] McMaster, D., and K. McCloghrie, "Definitions of Managed
        Objects for IEEE 802.3 Repeater Devices", RFC 1516,
        September 1993.

   [12] McAnally, G., D. Gilbert, and J. Flick, "Conditional
        Grant of Rights to Specific Hewlett-Packard Patents In
        Conjunction With the Internet Engineering Task Force's
        Internet-Standard Network Management Framework", RFC 1988,
        August 1996.

   [13] Hewlett-Packard Company, US Patents 5,293,635 and
        5,421,024.

   [14] McCloghrie, K., and F. Kastenholz, "Evolution of the
        Interfaces Group of MIB-II", RFC 1573, January 1994.

7.  Security Considerations

   Security issues are not discussed in this memo.

8.  Authors' Addresses

   Kathryn de Graaf
   3Com Corporation
   118 Turnpike Rd.
   Southborough, MA 01772 USA

   Phone: (508)229-1627
   Fax: (508)490-5882
   EMail: kdegraaf@isd.3com.com


   Dan Romascanu
   Madge Networks (Israel) Ltd.
   Atidim Technology Park, Bldg. 3
   Tel Aviv 61131, Israel

   Phone: 972-3-6458414, 6458458
   Fax: 972-3-6487146
   EMail: dromasca@madge.com
Top   ToC   RFC2108 - Page 82
   Donna McMaster
   Cisco Systems Inc.
   170 West Tasman Drive
   San Jose, CA 95134

   Phone: (408) 526-5260
   EMail: mcmaster@cisco.com


   Keith McCloghrie
   Cisco Systems Inc.
   170 West Tasman Drive
   San Jose, CA 95134

   Phone: (408) 526-5260
   EMail: kzm@cisco.com