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RFC 5528

Camellia Counter Mode and Camellia Counter with CBC-MAC Mode Algorithms

Pages: 22
Informational

Top   ToC   RFC5528 - Page 1
Network Working Group                                            A. Kato
Request for Comments: 5528                      NTT Software Corporation
Category: Informational                                         M. Kanda
                                                                     NTT
                                                                S. Kanno
                                                NTT Software Corporation
                                                              April 2009


Camellia Counter Mode and Camellia Counter with CBC-MAC Mode Algorithms

Status of This Memo

   This memo provides information for the Internet community.  It does
   not specify an Internet standard of any kind.  Distribution of this
   memo is unlimited.

Copyright Notice

   Copyright (c) 2009 IETF Trust and the persons identified as the
   document authors.  All rights reserved.

   This document is subject to BCP 78 and the IETF Trust's Legal
   Provisions Relating to IETF Documents in effect on the date of
   publication of this document (http://trustee.ietf.org/license-info).
   Please review these documents carefully, as they describe your rights
   and restrictions with respect to this document.

Abstract

This document describes the algorithms and presents test vectors for the Camellia block cipher algorithm in Counter mode (CTR) and Counter with Cipher Block Chaining MAC mode (CCM). The purpose of this document is to make the Camellia-CTR and Camellia-CCM algorithm conveniently available to the Internet Community.
Top   ToC   RFC5528 - Page 2

Table of Contents

1. Introduction ....................................................2 1.1. Terminology ................................................3 2. The Camellia Cipher Algorithm ...................................3 2.1. Key Size ...................................................3 2.2. Weak Keys ..................................................3 2.3. Block Size and Padding .....................................3 2.4. Performance ................................................4 3. Modes of Operation ..............................................4 4. Test Vectors ....................................................4 4.1. Camellia-CTR ...............................................4 4.2. Camellia-CCM ...............................................7 5. Security Considerations ........................................20 6. Acknowledgments ................................................20 7. References .....................................................20 7.1. Normative References ......................................20 7.2. Informative References ....................................20

1. Introduction

This document describes the use of the Camellia block cipher algorithm in Counter (CTR) mode and Counter with CBC-MAC (CCM) mode. Camellia is a symmetric cipher with a Feistel structure. Camellia was developed jointly by NTT and Mitsubishi Electric Corporation in 2000. It was designed to withstand all known cryptanalytic attacks, and it has been scrutinized by worldwide cryptographic experts. Camellia is suitable for implementation in software and hardware, offering encryption speed in software and hardware implementations that is comparable to Advanced Encryption Standard (AES) [5]. Camellia supports 128-bit block size and 128-, 192-, and 256-bit key lengths, i.e., the same interface specifications as the AES. Therefore, it is easy to implement Camellia-based algorithms by replacing the AES block of AES-based algorithms with a Camellia block. Camellia already has been adopted by the IETF and other international standardization organizations; in particular, the IETF has published specifications for the use of Camellia with IPsec [6], TLS [7], Secure/Multipurpose Internet Mail Extensions (S/MIME) [8], and XML Securiy [9]. Camellia is one of the three ISO/IEC international standard [10] 128-bit block ciphers (Camellia, AES, and Super Effective and Efficient Delivery (SEED)). Camellia was selected as a recommended cryptographic primitive by the EU NESSIE (New European Schemes for Signatures, Integrity and Encryption) project [11] and
Top   ToC   RFC5528 - Page 3
   was included in the list of cryptographic techniques for Japanese
   e-Government systems that was selected by the Japanese CRYPTREC
   (Cryptography Research and Evaluation Committees) [12].

   Since optimized source code is provided under several open source
   licenses [13], Camellia has also been adopted by several open source
   projects (OpenSSL, FreeBSD, Linux, and Firefox).

   The algorithm specification and object identifiers are described in
   [1].

   The Camellia web site [14] contains a wealth of information about
   Camellia, including detailed specification, security analysis,
   performance figures, reference implementation, optimized
   implementation, test vectors (TVs), and intellectual property
   information.

1.1. Terminology

The key words "MUST", "MUST NOT", "REQUIRED", "SHALL", "SHALL NOT", "SHOULD", "SHOULD NOT", "RECOMMENDED", "MAY", and "OPTIONAL" in this document are to be interpreted as described in RFC 2119 [2]. All multi-octet values in this document are encoded and represented in network byte order, i.e., most significant octet first.

2. The Camellia Cipher Algorithm

All symmetric block cipher algorithms share common characteristics and variables, including mode, key size, weak keys, and block size. The following sections contain descriptions of the relevant characteristics of Camellia.

2.1. Key Size

Camellia supports three key sizes: 128 bits, 192 bits, and 256 bits. The default key size is 128 bits, and all implementations MUST support this key size. Implementations MAY also support key sizes of 192 bits and 256 bits.

2.2. Weak Keys

At the time of writing this document, there are no known weak keys for Camellia.

2.3. Block Size and Padding

Camellia uses a block size of 16 octets (128 bits).
Top   ToC   RFC5528 - Page 4
   Padding is required by the algorithm to maintain a 16-octet (128-bit)
   block size.  Padding MUST be added such that the data to be encrypted
   has a length that is a multiple of 16 octets.

   Because of the algorithm-specific padding requirement, no additional
   padding is required to ensure that the ciphertext terminates on a
   4-octet boundary (i.e., maintaining a 16-octet block size guarantees
   that the Encapsulating Security Payload (ESP) Pad Length and Next
   Header fields will be right aligned within a 4-octet word).
   Additional padding MAY be included as long as the 16-octet block size
   is maintained.

2.4. Performance

Performance figures for Camellia are available at [14]. The NESSIE project has reported on the performance of optimized implementations independently [11].

3. Modes of Operation

Camellia Counter (Camellia-CTR) mode and Camellia Counter with CBC- MAC (Camellia-CCM) mode are based on [3][15][4]. CTR mode [3] behaves like a stream cipher, but is based on a block cipher primitive (that is, CTR mode operation of a block cipher results in a stream cipher). CCM mode [15][4] is a generic authenticate-and-encrypt block cipher mode. In this specification, CCM is used with the Camellia [1] block cipher.

4. Test Vectors

4.1. Camellia-CTR

This section contains nine TVs, which can be used to confirm that an implementation has correctly implemented Camellia-CTR. The first three TVs use Camellia with a 128-bit key; the next three TVs use Camellia with a 192-bit key; and the last three TVs use Camellia with a 256-bit key.
Top   ToC   RFC5528 - Page 5
   TV #1: Encrypting 16 octets using Camellia-CTR with 128-bit key
   Camellia Key     : AE 68 52 F8 12 10 67 CC 4B F7 A5 76 55 77 F3 9E
   Camellia-CTR IV  : 00 00 00 00 00 00 00 00
   Nonce            : 00 00 00 30
   Plaintext        : 53 69 6E 67 6C 65 20 62 6C 6F 63 6B 20 6D 73 67
   Counter Block (1): 00 00 00 30 00 00 00 00 00 00 00 00 00 00 00 01
   Key Stream    (1): 83 F4 AC FD EE 71 41 F8 4C E8 1F 1D FB 72 78 58
   Ciphertext       : D0 9D C2 9A 82 14 61 9A 20 87 7C 76 DB 1F 0B 3F

   TV #2: Encrypting 32 octets using Camellia-CTR with 128-bit key
   Camellia Key     : 7E 24 06 78 17 FA E0 D7 43 D6 CE 1F 32 53 91 63
   Camellia-CTR IV  : C0 54 3B 59 DA 48 D9 0B
   Nonce            : 00 6C B6 DB
   Plaintext        : 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
                    : 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F
   Counter Block (1): 00 6C B6 DB C0 54 3B 59 DA 48 D9 0B 00 00 00 01
   Key Stream    (1): DB F2 C5 8E C4 86 90 D3 D2 75 9A 7C 69 B6 C5 4B
   Counter Block (2): 00 6C B6 DB C0 54 3B 59 DA 48 D9 0B 00 00 00 02
   Key Stream    (2): 3B 9F 9C 1C 25 E5 CA B0 34 6D 0D F8 4F 7D FE 57
   Ciphertext       : DB F3 C7 8D C0 83 96 D4 DA 7C 90 77 65 BB CB 44
                    : 2B 8E 8E 0F 31 F0 DC A7 2C 74 17 E3 53 60 E0 48

   TV #3: Encrypting 36 octets using Camellia-CTR with 128-bit key
   Camellia Key     : 76 91 BE 03 5E 50 20 A8 AC 6E 61 85 29 F9 A0 DC
   Camellia-CTR IV  : 27 77 7F 3F 4A 17 86 F0
   Nonce            : 00 E0 01 7B
   Plaintext        : 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
                    : 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F
                    : 20 21 22 23
   Counter Block (1): 00 E0 01 7B 27 77 7F 3F 4A 17 86 F0 00 00 00 01
   Key Stream    (1): B1 9C 1D CE CF 70 ED 8F 27 8D 96 E9 41 88 C1 7C
   Counter Block (2): 00 E0 01 7B 27 77 7F 3F 4A 17 86 F0 00 00 00 02
   Key Stream    (2): 8C F7 59 38 48 88 65 E6 57 34 47 86 D2 85 97 D2
   Counter Block (3): 00 E0 01 7B 27 77 7F 3F 4A 17 86 F0 00 00 00 03
   Key Stream    (3): FF 71 A4 B5 D8 86 12 53 6A 9D 10 A1 13 0F 14 F8
   Ciphertext       : B1 9D 1F CD CB 75 EB 88 2F 84 9C E2 4D 85 CF 73
                    : 9C E6 4B 2B 5C 9D 73 F1 4F 2D 5D 9D CE 98 89 CD
                    : DF 50 86 96

   TV #4: Encrypting 16 octets using Camellia-CTR with 192-bit key
   Camellia Key     : 16 AF 5B 14 5F C9 F5 79 C1 75 F9 3E 3B FB 0E ED
                    : 86 3D 06 CC FD B7 85 15
   Camellia-CTR IV  : 36 73 3C 14 7D 6D 93 CB
   Nonce            : 00 00 00 48
   Plaintext        : 53 69 6E 67 6C 65 20 62 6C 6F 63 6B 20 6D 73 67
   Counter Block (1): 00 00 00 48 36 73 3C 14 7D 6D 93 CB 00 00 00 01
   Key Stream    (1): 70 10 57 F9 E6 E8 0B 49 7A 1F 4C AC AB F3 E5 F1
   Ciphertext       : 23 79 39 9E 8A 8D 2B 2B 16 70 2F C7 8B 9E 96 96
Top   ToC   RFC5528 - Page 6
   TV #5: Encrypting 32 octets using Camellia-CTR with 192-bit key
   Camellia Key     : 7C 5C B2 40 1B 3D C3 3C 19 E7 34 08 19 E0 F6 9C
                    : 67 8C 3D B8 E6 F6 A9 1A
   Camellia-CTR IV  : 02 0C 6E AD C2 CB 50 0D
   Nonce            : 00 96 B0 3B
   Plaintext        : 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
                    : 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F
   Counter Block (1): 00 96 B0 3B 02 0C 6E AD C2 CB 50 0D 00 00 00 01
   Key Stream    (1): 7D EE 36 F4 A1 D5 E2 12 6F 42 75 F7 A2 6A C9 52
   Counter Block (2): 00 96 B0 3B 02 0C 6E AD C2 CB 50 0D 00 00 00 02
   Key Stream    (2): C0 09 AA 7C E6 25 47 F7 4E 20 30 82 EF 47 52 F2
   Ciphertext       : 7D EF 34 F7 A5 D0 E4 15 67 4B 7F FC AE 67 C7 5D
                    : D0 18 B8 6F F2 30 51 E0 56 39 2A 99 F3 5A 4C ED

   TV #6: Encrypting 36 octets using Camellia-CTR with 192-bit key
   Camellia Key     : 02 BF 39 1E E8 EC B1 59 B9 59 61 7B 09 65 27 9B
                    : F5 9B 60 A7 86 D3 E0 FE
   Camellia-CTR IV  : 5C BD 60 27 8D CC 09 12
   Nonce            : 00 07 BD FD
   Plaintext        : 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
                    : 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F
                    : 20 21 22 23
   Counter Block (1): 00 07 BD FD 5C BD 60 27 8D CC 09 12 00 00 00 01
   Key Stream    (1): 57 11 E7 55 E5 4D 7C 27 BD A5 04 78 FD 93 40 77
   Counter Block (2): 00 07 BD FD 5C BD 60 27 8D CC 09 12 00 00 00 02
   Key Stream    (2): 66 E2 6D CF 85 A4 F9 5A 55 B4 F2 FD 7A BB 53 11
   Counter Block (3): 00 07 BD FD 5C BD 60 27 8D CC 09 12 00 00 00 03
   Key Stream    (3): F5 76 89 74 63 52 A8 C5 1E 82 DE 66 C3 9F 38 34
   Ciphertext       : 57 10 E5 56 E1 48 7A 20 B5 AC 0E 73 F1 9E 4E 78
                    : 76 F3 7F DC 91 B1 EF 4D 4D AD E8 E6 66 A6 4D 0E
                    : D5 57 AB 57

   TV #7: Encrypting 16 octets using Camellia-CTR with 256-bit key
   Camellia Key     : 77 6B EF F2 85 1D B0 6F 4C 8A 05 42 C8 69 6F 6C
                    : 6A 81 AF 1E EC 96 B4 D3 7F C1 D6 89 E6 C1 C1 04
   Camellia-CTR IV  : DB 56 72 C9 7A A8 F0 B2
   Nonce            : 00 00 00 60
   Plaintext        : 53 69 6E 67 6C 65 20 62 6C 6F 63 6B 20 6D 73 67
   Counter Block (1): 00 00 00 60 DB 56 72 C9 7A A8 F0 B2 00 00 00 01
   Key Stream    (1): 67 68 97 AF 48 1B DF AC D1 06 F7 1A 6C 76 C8 76
   Ciphertext       : 34 01 F9 C8 24 7E FF CE BD 69 94 71 4C 1B BB 11
Top   ToC   RFC5528 - Page 7
   TV #8: Encrypting 32 octets using Camellia-CTR with 256-bit key
   Camellia Key     : F6 D6 6D 6B D5 2D 59 BB 07 96 36 58 79 EF F8 86
                    : C6 6D D5 1A 5B 6A 99 74 4B 50 59 0C 87 A2 38 84
   Camellia-CTR IV  : C1 58 5E F1 5A 43 D8 75
   Nonce            : 00 FA AC 24
   Plaintext        : 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
                    : 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F
   Counter Block (1): 00 FA AC 24 C1 58 5E F1 5A 43 D8 75 00 00 00 01
   Key Stream    (1): D6 C2 01 91 20 6A 7E 0F A0 35 21 29 A4 8E 90 4A
   Counter Block (2): 00 FA AC 24 C1 58 5E F1 5A 43 D8 75 00 00 00 02
   Key Stream    (2): F5 0D C6 99 08 CA 56 79 A4 85 D8 C8 B7 9E 5F 17
   Ciphertext       : D6 C3 03 92 24 6F 78 08 A8 3C 2B 22 A8 83 9E 45
                    : E5 1C D4 8A 1C DF 40 6E BC 9C C2 D3 AB 83 41 08

   TV #9: Encrypting 36 octets using Camellia-CTR with 256-bit key
   Camellia Key     : FF 7A 61 7C E6 91 48 E4 F1 72 6E 2F 43 58 1D E2
                    : AA 62 D9 F8 05 53 2E DF F1 EE D6 87 FB 54 15 3D
   Camellia-CTR IV  : 51 A5 1D 70 A1 C1 11 48
   Nonce            : 00 1C C5 B7
   Plaintext        : 00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
                    : 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F
                    : 20 21 22 23
   Counter Block (1): 00 1C C5 B7 51 A5 1D 70 A1 C1 11 48 00 00 00 01
   Key Stream    (1): A4 DB 21 FF E2 A0 F9 AD 65 6D A4 91 0A 5F AA 23
   Counter Block (2): 00 1C C5 B7 51 A5 1D 70 A1 C1 11 48 00 00 00 02
   Key Stream    (2): C1 70 B1 58 71 EC 71 88 6D D9 05 0B 03 6C 39 70
   Counter Block (3): 00 1C C5 B7 51 A5 1D 70 A1 C1 11 48 00 00 00 03
   Key Stream    (3): 35 CE 2F AE 90 78 B3 72 F5 76 12 39 1F 8B AF BF
   Ciphertext       : A4 DA 23 FC E6 A5 FF AA 6D 64 AE 9A 06 52 A4 2C
                    : D1 61 A3 4B 65 F9 67 9F 75 C0 1F 10 1F 71 27 6F
                    : 15 EF 0D 8D

4.2. Camellia-CCM

This section contains twenty four TVs, which can be used to confirm that an implementation has correctly implemented Camellia-CCM. In each of these TVs, the least significant sixteen bits of the counter block is used for the block counter, and the nonce is 13 octets. Some of the TVs include an eight octet authentication value, and others include a ten octet authentication value.
Top   ToC   RFC5528 - Page 8
   =============== Packet Vector #1 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 03  02 01 00 A0  A1 A2 A3 A4  A5
   Total packet length =   31. [Input (8 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E
   CBC IV in: 59 00 00 00  03 02 01 00  A0 A1 A2 A3  A4 A5 00 17
   CBC IV out:D4 DB CD 92  A8 96 41 56  1D 0D BB D0  D5 7F 7E 1D
   After xor: D4 D3 CD 93  AA 95 45 53  1B 0A BB D0  D5 7F 7E 1D   [hdr]
   After CAM: BD 84 03 80  73 59 37 B7  CE F5 E4 BA  1B 18 54 DC
   After xor: B5 8D 09 8B  7F 54 39 B8  DE E4 F6 A9  0F 0D 42 CB   [msg]
   After CAM: CE 21 82 9C  F6 F2 4D A2  CB 35 D1 FD  81 27 63 EC
   After xor: D6 38 98 87  EA EF 53 A2  CB 35 D1 FD  81 27 63 EC   [msg]
   After CAM: 20 11 FE E2  53 B1 A7 DB  02 77 FA 37  6D 78 EE 10
   MIC tag  : 20 11 FE E2  53 B1 A7 DB
   CTR Start: 01 00 00 00  03 02 01 00  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: B2 7A 7B 8E  EB 14 3F 0B  82 E2 98 4C  06 44 CC 42
   CTR[0002]: E2 E2 D3 52  98 97 13 45  D1 63 22 90  E7 F8 15 4A
   CTR[MIC ]: DC BF 30 96  38 8C 1E 76
   Total packet length =   39. [Encrypted]
              00 01 02 03  04 05 06 07  BA 73 71 85  E7 19 31 04
              92 F3 8A 5F  12 51 DA 55  FA FB C9 49  84 8A 0D FC
              AE CE 74 6B  3D B9 AD

   =============== Packet Vector #2 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 04  03 02 01 A0  A1 A2 A3 A4  A5
   Total packet length =   32. [Input (8 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E 1F
   CBC IV in: 59 00 00 00  04 03 02 01  A0 A1 A2 A3  A4 A5 00 18
   CBC IV out:07 0B 22 50  8A 24 3C DD  5B BA 54 DB  60 52 88 06
   After xor: 07 03 22 51  88 27 38 D8  5D BD 54 DB  60 52 88 06   [hdr]
   After CAM: 10 FD C2 F2  90 4A 9F 96  B0 4F 62 A4  A1 A9 31 1E
   After xor: 18 F4 C8 F9  9C 47 91 99  A0 5E 70 B7  B5 BC 27 09   [msg]
   After CAM: E4 C8 82 02  89 55 5C 15  CE 7F E4 60  B1 B9 5A 08
   After xor: FC D1 98 19  95 48 42 0A  CE 7F E4 60  B1 B9 5A 08   [msg]
   After CAM: D2 96 BA 4F  83 DE B5 DF  A2 19 08 F7  47 4E 3C 40
   MIC tag  : D2 96 BA 4F  83 DE B5 DF
   CTR Start: 01 00 00 00  04 03 02 01  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: 55 2C 6E B4  82 A2 EF D6  85 37 FE 12  79 0E E6 55
   CTR[0002]: 54 E2 C8 D6  7E 99 91 2C  F2 8A D7 8E  83 04 10 36
   CTR[MIC ]: B2 24 93 12  71 9C 36 37
   Total packet length =   40. [Encrypted]
              00 01 02 03  04 05 06 07  5D 25 64 BF  8E AF E1 D9
              95 26 EC 01  6D 1B F0 42  4C FB D2 CD  62 84 8F 33
              60 B2 29 5D  F2 42 83 E8
Top   ToC   RFC5528 - Page 9
   =============== Packet Vector #3 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 05  04 03 02 A0  A1 A2 A3 A4  A5
   Total packet length =   33. [Input (8 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E 1F
              20
   CBC IV in: 59 00 00 00  05 04 03 02  A0 A1 A2 A3  A4 A5 00 19
   CBC IV out:6F 69 15 DF  A6 A0 DF 24  84 A7 37 88  A3 65 F9 2E
   After xor: 6F 61 15 DE  A4 A3 DB 21  82 A0 37 88  A3 65 F9 2E   [hdr]
   After CAM: 59 5D 99 48  79 04 DA C9  13 93 36 C9  11 A8 09 1D
   After xor: 51 54 93 43  75 09 D4 C6  03 82 24 DA  05 BD 1F 0A   [msg]
   After CAM: 1A 43 D7 19  65 43 97 C1  43 6F 4F 11  A7 6C 6B ED
   After xor: 02 5A CD 02  79 5E 89 DE  63 6F 4F 11  A7 6C 6B ED   [msg]
   After CAM: 30 0B 06 8A  A0 D1 4D C5  9E 44 22 84  82 45 42 0B
   MIC tag  : 30 0B 06 8A  A0 D1 4D C5
   CTR Start: 01 00 00 00  05 04 03 02  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: 89 FF 69 DD  CB 75 76 18  E9 31 24 1B  AD 97 BB 02
   CTR[0002]: C4 32 A7 9C  CB 4B E9 8D  24 A8 F0 AB  C6 87 16 11
   CTR[MIC ]: C5 5A D0 E2  8F F2 E7 83
   Total packet length =   41. [Encrypted]
              00 01 02 03  04 05 06 07  81 F6 63 D6  C7 78 78 17
              F9 20 36 08  B9 82 AD 15  DC 2B BD 87  D7 56 F7 92
              04 F5 51 D6  68 2F 23 AA  46

   =============== Packet Vector #4 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 06  05 04 03 A0  A1 A2 A3 A4  A5
   Total packet length =   31. [Input (12 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E
   CBC IV in: 59 00 00 00  06 05 04 03  A0 A1 A2 A3  A4 A5 00 13
   CBC IV out:F5 51 CF 6C  7C F7 D4 0B  2B 76 F1 6B  57 F0 19 FE
   After xor: F5 5D CF 6D  7E F4 D0 0E  2D 71 F9 62  5D FB 19 FE   [hdr]
   After CAM: 02 2B 21 1B  EB 97 02 3B  F8 10 7D CC  62 14 E5 7C
   After xor: 0E 26 2F 14  FB 86 10 28  EC 05 6B DB  7A 0D FF 67   [msg]
   After CAM: 48 14 A4 2D  31 25 1C 37  19 C5 6F DD  5A 37 81 42
   After xor: 54 09 BA 2D  31 25 1C 37  19 C5 6F DD  5A 37 81 42   [msg]
   After CAM: CF 85 25 D2  80 D5 F0 09  53 2C 9D 43  4E F3 04 47
   MIC tag  : CF 85 25 D2  80 D5 F0 09
   CTR Start: 01 00 00 00  06 05 04 03  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: C6 E2 10 8D  62 00 A2 9C  6F CC 19 1F  DF 6B 92 DB
   CTR[0002]: 6C B9 BE EE  1E A2 E9 B3  2D D6 C2 9A  E8 26 D5 C2
   CTR[MIC ]: 44 BF B6 E8  E3 31 67 A9
   Total packet length =   39. [Encrypted]
              00 01 02 03  04 05 06 07  08 09 0A 0B  CA EF 1E 82
              72 11 B0 8F  7B D9 0F 08  C7 72 88 C0  70 A4 A0 8B
              3A 93 3A 63  E4 97 A0
Top   ToC   RFC5528 - Page 10
   =============== Packet Vector #5 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 07  06 05 04 A0  A1 A2 A3 A4  A5
   Total packet length =   32. [Input (12 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E 1F
   CBC IV in: 59 00 00 00  07 06 05 04  A0 A1 A2 A3  A4 A5 00 14
   CBC IV out:73 72 9D 76  7A BD B9 82  60 3A 12 7B  EF 26 FB 80
   After xor: 73 7E 9D 77  78 BE BD 87  66 3D 1A 72  E5 2D FB 80   [hdr]
   After CAM: E1 B7 A6 72  E2 5C 87 75  91 21 22 A4  07 13 CD 5B
   After xor: ED BA A8 7D  F2 4D 95 66  85 34 34 B3  1F 0A D7 40   [msg]
   After CAM: 13 2F 58 D9  5D 0F 95 B8  90 BF 6F 1D  31 84 54 C7
   After xor: 0F 32 46 C6  5D 0F 95 B8  90 BF 6F 1D  31 84 54 C7   [msg]
   After CAM: 47 8F 1E B0  71 24 8B 13  AF C8 C8 44  E6 0F 88 B6
   MIC tag  : 47 8F 1E B0  71 24 8B 13
   CTR Start: 01 00 00 00  07 06 05 04  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: 26 DE B4 D6  5F D4 3C 81  AA 56 98 95  64 09 39 A2
   CTR[0002]: 76 97 69 3A  21 13 0C 39  2E 4E EB BF  48 7B 24 BE
   CTR[MIC ]: C8 2E 65 17  82 15 50 1A
   Total packet length =   40. [Encrypted]
              00 01 02 03  04 05 06 07  08 09 0A 0B  2A D3 BA D9
              4F C5 2E 92  BE 43 8E 82  7C 10 23 B9  6A 8A 77 25
              8F A1 7B A7  F3 31 DB 09

   =============== Packet Vector #6 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 08  07 06 05 A0  A1 A2 A3 A4  A5
   Total packet length =   33. [Input (12 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E 1F
              20
   CBC IV in: 59 00 00 00  08 07 06 05  A0 A1 A2 A3  A4 A5 00 15
   CBC IV out:EB 59 05 CC  3F 52 61 10  26 24 75 93  DD B9 A0 F4
   After xor: EB 55 05 CD  3D 51 65 15  20 23 7D 9A  D7 B2 A0 F4   [hdr]
   After CAM: 18 A9 AE A4  3D D2 A9 11  6C 0A E5 4F  40 D1 4D 9F
   After xor: 14 A4 A0 AB  2D C3 BB 02  78 1F F3 58  58 C8 57 84   [msg]
   After CAM: FA C4 13 18  98 54 1B 54  93 9C 64 B8  CB FD 5B 18
   After xor: E6 D9 0D 07  B8 54 1B 54  93 9C 64 B8  CB FD 5B 18   [msg]
   After CAM: 49 E6 E8 ED  32 FB CA 2F  2E 55 CD AF  D0 F2 B3 05
   MIC tag  : 49 E6 E8 ED  32 FB CA 2F
   CTR Start: 01 00 00 00  08 07 06 05  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: F2 A8 46 04  B5 2E BA C0  D7 51 34 BD  D6 54 FC 64
   CTR[0002]: E6 26 A9 24  8B E6 86 CB  92 D6 FB FC  2E F2 91 98
   CTR[MIC ]: E2 D0 49 03  7D 1B 34 07
   Total packet length =   41. [Encrypted]
              00 01 02 03  04 05 06 07  08 09 0A 0B  FE A5 48 0B
              A5 3F A8 D3  C3 44 22 AA  CE 4D E6 7F  FA 3B B7 3B
              AB AB 36 A1  EE 4F E0 FE  28
Top   ToC   RFC5528 - Page 11
   =============== Packet Vector #7 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 09  08 07 06 A0  A1 A2 A3 A4  A5
   Total packet length =   31. [Input (8 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E
   CBC IV in: 61 00 00 00  09 08 07 06  A0 A1 A2 A3  A4 A5 00 17
   CBC IV out:AC F1 5D 79  99 1A 15 BF  5C DC F6 C4  45 AE 1F CB
   After xor: AC F9 5D 78  9B 19 11 BA  5A DB F6 C4  45 AE 1F CB   [hdr]
   After CAM: E9 C0 AC FD  C7 E8 E7 1D  FA E8 8B 66  95 9E 01 45
   After xor: E1 C9 A6 F6  CB E5 E9 12  EA F9 99 75  81 8B 17 52   [msg]
   After CAM: 9C FF ED 72  09 A6 7D 2A  48 B7 29 BF  D8 BE 39 59
   After xor: 84 E6 F7 69  15 BB 63 2A  48 B7 29 BF  D8 BE 39 59   [msg]
   After CAM: 4F 41 FA DE  B2 58 F3 32  54 0A 55 7A  80 4A A3 F5
   MIC tag  : 4F 41 FA DE  B2 58 F3 32  54 0A
   CTR Start: 01 00 00 00  09 08 07 06  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: 5C 5A 2A 2D  E9 41 1F 95  9D 27 CB FF  7A 0B CF 63
   CTR[0002]: 0E D1 6A 97  57 41 32 4F  33 1B 4A 42  B1 4A 54 63
   CTR[MIC ]: E3 EE 59 62  7D 22 BD 8D  C1 79
   Total packet length =   41. [Encrypted]
              00 01 02 03  04 05 06 07  54 53 20 26  E5 4C 11 9A
              8D 36 D9 EC  6E 1E D9 74  16 C8 70 8C  4B 5C 2C AC
              AF A3 BC CF  7A 4E BF 95  73

   =============== Packet Vector #8 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 0A  09 08 07 A0  A1 A2 A3 A4  A5
   Total packet length =   32. [Input (8 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E 1F
   CBC IV in: 61 00 00 00  0A 09 08 07  A0 A1 A2 A3  A4 A5 00 18
   CBC IV out:AD CA 1C 1D  45 E7 E2 62  58 D5 DA 46  D8 2F 69 3A
   After xor: AD C2 1C 1C  47 E4 E6 67  5E D2 DA 46  D8 2F 69 3A   [hdr]
   After CAM: FA DE 0E B4  3E CA C1 E9  69 BB 8C A4  7C 0D 80 8F
   After xor: F2 D7 04 BF  32 C7 CF E6  79 AA 9E B7  68 18 96 98   [msg]
   After CAM: D2 87 35 C2  D0 E4 AE 4E  BC C2 99 FF  B3 77 F8 A1
   After xor: CA 9E 2F D9  CC F9 B0 51  BC C2 99 FF  B3 77 F8 A1   [msg]
   After CAM: BD F6 FB 55  9E 90 C0 E7  DF 4B 0C 37  DC 42 32 A2
   MIC tag  : BD F6 FB 55  9E 90 C0 E7  DF 4B
   CTR Start: 01 00 00 00  0A 09 08 07  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: 82 D8 91 0B  16 8A DF 47  E4 C8 39 FC  20 47 4A DB
   CTR[0002]: FB BF 26 7E  0E BB EB 6A  07 4E 29 CF  3D 12 E6 DB
   CTR[MIC ]: CE 7E 1F C4  A0 61 87 E6  2B 0A
   Total packet length =   42. [Encrypted]
              00 01 02 03  04 05 06 07  8A D1 9B 00  1A 87 D1 48
              F4 D9 2B EF  34 52 5C CC  E3 A6 3C 65  12 A6 F5 75
              73 88 E4 91  3E F1 47 01  F4 41
Top   ToC   RFC5528 - Page 12
   =============== Packet Vector #9 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 0B  0A 09 08 A0  A1 A2 A3 A4  A5
   Total packet length =   33. [Input (8 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E 1F
              20
   CBC IV in: 61 00 00 00  0B 0A 09 08  A0 A1 A2 A3  A4 A5 00 19
   CBC IV out:D0 A9 A5 94  00 63 86 40  11 0D DB 40  CA F8 4A 9C
   After xor: D0 A1 A5 95  02 60 82 45  17 0A DB 40  CA F8 4A 9C   [hdr]
   After CAM: 7B CA 4E 2D  79 82 0D 1E  15 22 DD E8  37 B9 B1 F0
   After xor: 73 C3 44 26  75 8F 03 11  05 33 CF FB  23 AC A7 E7   [msg]
   After CAM: 6B 75 9F 83  C0 8F 56 64  F2 FA D5 7F  67 01 B8 21
   After xor: 73 6C 85 98  DC 92 48 7B  D2 FA D5 7F  67 01 B8 21   [msg]
   After CAM: 7D B7 BE FF  72 F3 26 74  9E 20 07 28  1E 5B 1A 8A
   MIC tag  : 7D B7 BE FF  72 F3 26 74  9E 20
   CTR Start: 01 00 00 00  0B 0A 09 08  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: 55 B9 87 69  4C 73 60 3E  C6 1E 8E B1  D2 11 62 36
   CTR[0002]: 82 D9 A4 4B  DC C9 BB 68  A7 FE 15 A5  19 51 57 87
   CTR[MIC ]: E9 61 5C CF  BF D6 EF 8A  21 A7
   Total packet length =   43. [Encrypted]
              00 01 02 03  04 05 06 07  5D B0 8D 62  40 7E 6E 31
              D6 0F 9C A2  C6 04 74 21  9A C0 BE 50  C0 D4 A5 77
              87 94 D6 E2  30 CD 25 C9  FE BF 87

   =============== Packet Vector #10 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 0C  0B 0A 09 A0  A1 A2 A3 A4  A5
   Total packet length =   31. [Input (12 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E
   CBC IV in: 61 00 00 00  0C 0B 0A 09  A0 A1 A2 A3  A4 A5 00 13
   CBC IV out:B1 85 73 A3  1C 6F EC 01  90 E3 CE 94  27 11 04 B9
   After xor: B1 89 73 A2  1E 6C E8 04  96 E4 C6 9D  2D 1A 04 B9   [hdr]
   After CAM: A6 AD EA 9C  FA 3F 76 78  4C 17 8A F3  DC 69 F0 82
   After xor: AA A0 E4 93  EA 2E 64 6B  58 02 9C E4  C4 70 EA 99   [msg]
   After CAM: 35 50 B7 27  78 F8 C6 BF  02 4B 65 60  05 C0 E1 ED
   After xor: 29 4D A9 27  78 F8 C6 BF  02 4B 65 60  05 C0 E1 ED   [msg]
   After CAM: 3D B5 A6 E6  85 AF 1C 58  80 B0 32 2E  01 74 91 FC
   MIC tag  : 3D B5 A6 E6  85 AF 1C 58  80 B0
   CTR Start: 01 00 00 00  0C 0B 0A 09  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: D7 1C 82 C1  D1 A9 64 0F  93 69 CE 81  22 7E CC E8
   CTR[0002]: A7 A1 42 44  32 4E 69 FE  4C D0 36 65  A5 31 0B AB
   CTR[MIC ]: ED 27 3F 0D  94 5C 0E AA  B2 87
   Total packet length =   41. [Encrypted]
              00 01 02 03  04 05 06 07  08 09 0A 0B  DB 11 8C CE
              C1 B8 76 1C  87 7C D8 96  3A 67 D6 F3  BB BC 5C D0
              92 99 EB 11  F3 12 F2 32  37
Top   ToC   RFC5528 - Page 13
   =============== Packet Vector #11 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 0D  0C 0B 0A A0  A1 A2 A3 A4  A5
   Total packet length =   32. [Input (12 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E 1F
   CBC IV in: 61 00 00 00  0D 0C 0B 0A  A0 A1 A2 A3  A4 A5 00 14
   CBC IV out:45 DF B5 07  6F BB 10 EA  F1 15 15 AD  21 4F B0 0E
   After xor: 45 D3 B5 06  6D B8 14 EF  F7 12 1D A4  2B 44 B0 0E   [hdr]
   After CAM: 17 52 F9 6D  DD BC 5B 1C  1E EB 80 FC  F6 10 AC 03
   After xor: 1B 5F F7 62  CD AD 49 0F  0A FE 96 EB  EE 09 B6 18   [msg]
   After CAM: BE F0 A0 B9  EC 94 B6 B3  E8 EC 1B 82  14 14 09 87
   After xor: A2 ED BE A6  EC 94 B6 B3  E8 EC 1B 82  14 14 09 87   [msg]
   After CAM: 70 16 E4 F9  C4 2C 30 10  84 BF EC 69  34 89 91 FD
   MIC tag  : 70 16 E4 F9  C4 2C 30 10  84 BF
   CTR Start: 01 00 00 00  0D 0C 0B 0A  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: 70 C5 33 82  D4 80 11 41  4F 5D 2B D2  D2 67 B3 B0
   CTR[0002]: 9D 36 6E 49  39 C5 16 76  5C 1C 25 12  81 79 94 70
   CTR[MIC ]: 77 8B 4B 03  1E 3A FC DF  A8 F1
   Total packet length =   42. [Encrypted]
              00 01 02 03  04 05 06 07  08 09 0A 0B  7C C8 3D 8D
              C4 91 03 52  5B 48 3D C5  CA 7E A9 AB  81 2B 70 56
              07 9D AF FA  DA 16 CC CF  2C 4E

   =============== Packet Vector #12 ==================
   CAM Key:   C0 C1 C2 C3  C4 C5 C6 C7  C8 C9 CA CB  CC CD CE CF
   Nonce =    00 00 00 0E  0D 0C 0B A0  A1 A2 A3 A4  A5
   Total packet length =   33. [Input (12 cleartext header octets)]
              00 01 02 03  04 05 06 07  08 09 0A 0B  0C 0D 0E 0F
              10 11 12 13  14 15 16 17  18 19 1A 1B  1C 1D 1E 1F
              20
   CBC IV in: 61 00 00 00  0E 0D 0C 0B  A0 A1 A2 A3  A4 A5 00 15
   CBC IV out:81 E4 EB 1E  50 A9 70 CE  18 CA 1A 4B  68 39 80 2E
   After xor: 81 E8 EB 1F  52 AA 74 CB  1E CD 12 42  62 32 80 2E   [hdr]
   After CAM: 04 AB D9 62  34 B9 8F 32  8C 0F 08 3F  3D 87 9D 57
   After xor: 08 A6 D7 6D  24 A8 9D 21  98 1A 1E 28  25 9E 87 4C   [msg]
   After CAM: BD A2 EA CB  3A DA 6A E7  9F BB C2 2C  E6 4C 98 89
   After xor: A1 BF F4 D4  1A DA 6A E7  9F BB C2 2C  E6 4C 98 89   [msg]
   After CAM: B6 FC E1 46  D3 EA DC 91  E0 AB 10 AD  D8 55 E7 03
   MIC tag  : B6 FC E1 46  D3 EA DC 91  E0 AB
   CTR Start: 01 00 00 00  0E 0D 0C 0B  A0 A1 A2 A3  A4 A5 00 01
   CTR[0001]: 20 DE 55 87  30 C3 2C 69  B7 44 A6 FE  37 DE 89 7C
   CTR[0002]: 3F 96 32 D8  68 6D C2 B5  22 97 42 27  EB F9 26 5E
   CTR[MIC ]: 7D 45 AD 6F  94 93 E1 F5  4F DE
   Total packet length =   43. [Encrypted]
              00 01 02 03  04 05 06 07  08 09 0A 0B  2C D3 5B 88
              20 D2 3E 7A  A3 51 B0 E9  2F C7 93 67  23 8B 2C C7
              48 CB B9 4C  29 47 79 3D  64 AF 75
Top   ToC   RFC5528 - Page 14
   =============== Packet Vector #13 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 A9 70 11  0E 19 27 B1  60 B6 A3 1C  1C
   Total packet length =   31. [Input (8 cleartext header octets)]
              6B 7F 46 45  07 FA E4 96  C6 B5 F3 E6  CA 23 11 AE
              F7 47 2B 20  3E 73 5E A5  61 AD B1 7D  56 C5 A3
   CBC IV in: 59 00 A9 70  11 0E 19 27  B1 60 B6 A3  1C 1C 00 17
   CBC IV out:D7 24 B0 0F  B1 87 04 C6  C1 4E 90 37  AA F2 F1 F9
   After xor: D7 2C DB 70  F7 C2 03 3C  25 D8 90 37  AA F2 F1 F9   [hdr]
   After CAM: 9B 13 6D E3  D9 9F C3 6D  7D 0D B7 D8  A1 BF E9 BD
   After xor: 5D A6 9E 05  13 BC D2 C3  8A 4A 9C F8  9F CC B7 18   [msg]
   After CAM: F8 BF 25 7D  23 F8 D9 B5  82 E6 C9 3E  C8 9B 85 73
   After xor: 99 12 94 00  75 3D 7A B5  82 E6 C9 3E  C8 9B 85 73   [msg]
   After CAM: D9 D6 62 21  6D B2 CA FD  1F C6 FE 9D  2C AF 5B 69
   MIC tag  : D9 D6 62 21  6D B2 CA FD
   CTR Start: 01 00 A9 70  11 0E 19 27  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: 62 80 24 C1  FE AE CC 8C  67 38 55 98  CB 8E E5 E8
   CTR[0002]: F2 30 17 2F  1B 71 55 9F  8B CE 79 E5  13 01 FC 6A
   CTR[MIC ]: 9C 8E A2 0C  48 03 ED 13
   Total packet length =   39. [Encrypted]
              6B 7F 46 45  07 FA E4 96  A4 35 D7 27  34 8D DD 22
              90 7F 7E B8  F5 FD BB 4D  93 9D A6 52  4D B4 F6 45
              58 C0 2D 25  B1 27 EE

   =============== Packet Vector #14 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 83 CD 8C  E0 CB 42 B1  60 B6 A3 1C  1C
   Total packet length =   32. [Input (8 cleartext header octets)]
              98 66 05 B4  3D F1 5D E7  01 F6 CE 67  64 C5 74 48
              3B B0 2E 6B  BF 1E 0A BD  26 A2 25 72  B4 D8 0E E7
   CBC IV in: 59 00 83 CD  8C E0 CB 42  B1 60 B6 A3  1C 1C 00 18
   CBC IV out:A0 8A 29 78  36 23 1D 84  96 76 93 FF  0A 4C 92 7A
   After xor: A0 82 B1 1E  33 97 20 75  CB 91 93 FF  0A 4C 92 7A   [hdr]
   After CAM: 8C F5 F4 23  BF 09 1C 74  CD 47 00 C1  32 5D 5C 92
   After xor: 8D 03 3A 44  DB CC 68 3C  F6 F7 2E AA  8D 43 56 2F   [msg]
   After CAM: 69 DA 48 24  41 1E AC 8E  A9 0A CD 8B  DD 00 2B 9A
   After xor: 4F 78 6D 56  F5 C6 A2 69  A9 0A CD 8B  DD 00 2B 9A   [msg]
   After CAM: C2 03 3B 08  6D B3 CB 3B  2C C8 5D E7  76 A1 C0 44
   MIC tag  : C2 03 3B 08  6D B3 CB 3B
   CTR Start: 01 00 83 CD  8C E0 CB 42  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: 8B 16 9C 37  EB 7B BE DB  15 84 41 6E  5F C2 07 46
   CTR[0002]: E9 31 BB DD  4E E6 56 9B  68 95 13 5F  AB A4 DF EF
   CTR[MIC ]: 44 7E 55 14  25 C3 F3 3D
   Total packet length =   40. [Encrypted]
              98 66 05 B4  3D F1 5D E7  8A E0 52 50  8F BE CA 93
              2E 34 6F 05  E0 DC 0D FB  CF 93 9E AF  FA 3E 58 7C
              86 7D 6E 1C  48 70 38 06
Top   ToC   RFC5528 - Page 15
   =============== Packet Vector #15 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 5F 54 95  0B 18 F2 B1  60 B6 A3 1C  1C
   Total packet length =   33. [Input (8 cleartext header octets)]
              48 F2 E7 E1  A7 67 1A 51  CD F1 D8 40  6F C2 E9 01
              49 53 89 70  05 FB FB 8B  A5 72 76 F9  24 04 60 8E
              08
   CBC IV in: 59 00 5F 54  95 0B 18 F2  B1 60 B6 A3  1C 1C 00 19
   CBC IV out:76 74 53 37  95 23 3C F0  EB 77 CE 93  73 06 99 A8
   After xor: 76 7C 1B C5  72 C2 9B 97  F1 26 CE 93  73 06 99 A8   [hdr]
   After CAM: EF 79 8B 70  34 E4 D5 6B  57 3A F9 44  F0 AF D6 9A
   After xor: 22 88 53 30  5B 26 3C 6A  1E 69 70 34  F5 54 2D 11   [msg]
   After CAM: 63 BF 4E 10  01 79 38 0B  E4 EC C1 39  B2 B4 3B 8C
   After xor: C6 CD 38 E9  25 7D 58 85  EC EC C1 39  B2 B4 3B 8C   [msg]
   After CAM: 39 E1 0E FA  BD 2F 43 00  50 9E E7 EB  A4 FF 6B 8F
   MIC tag  : 39 E1 0E FA  BD 2F 43 00
   CTR Start: 01 00 5F 54  95 0B 18 F2  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: C5 47 A6 A2  73 49 1B 6F  0E 6D C9 F5  9C 12 3B 08
   CTR[0002]: C8 18 86 42  3C DB 35 C8  64 4D 8C 4C  58 01 47 27
   CTR[MIC ]: 91 E9 76 5D  2D 68 2E E5
   Total packet length =   41. [Encrypted]
              48 F2 E7 E1  A7 67 1A 51  08 B6 7E E2  1C 8B F2 6E
              47 3E 40 85  99 E9 C0 83  6D 6A F0 BB  18 DF 55 46
              6C A8 08 78  A7 90 47 6D  E5

   =============== Packet Vector #16 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 EC 60 08  63 31 9A B1  60 B6 A3 1C  1C
   Total packet length =   31. [Input (12 cleartext header octets)]
              DE 97 DF 3B  8C BD 6D 8E  50 30 DA 4C  B0 05 DC FA
              0B 59 18 14  26 A9 61 68  5A 99 3D 8C  43 18 5B
   CBC IV in: 59 00 EC 60  08 63 31 9A  B1 60 B6 A3  1C 1C 00 13
   CBC IV out:78 EE 05 5A  88 48 E3 5B  8A 45 46 8F  35 4F 0C A2
   After xor: 78 E2 DB CD  57 73 6F E6  E7 CB 16 BF  EF 03 0C A2   [hdr]
   After CAM: A9 C6 7F 15  00 1A C6 92  81 67 BD EC  DF D2 35 C9
   After xor: 19 C3 A3 EF  0B 43 DE 86  A7 CE DC 84  85 4B 08 45   [msg]
   After CAM: 7C A8 9C 90  46 42 4B E2  4D 96 DF CF  BA 12 FD 18
   After xor: 3F B0 C7 90  46 42 4B E2  4D 96 DF CF  BA 12 FD 18   [msg]
   After CAM: 89 C7 B4 E8  A4 24 8C 6C  52 ED 34 50  E3 53 AD F5
   MIC tag  : 89 C7 B4 E8  A4 24 8C 6C
   CTR Start: 01 00 EC 60  08 63 31 9A  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: D3 B2 57 B3  6C E8 86 CF  91 9A AC 79  4E 6F 73 3E
   CTR[0002]: 65 10 C8 72  39 AF 0F 52  9F D0 A4 DF  54 BF D6 EB
   CTR[MIC ]: E1 04 E0 6A  29 B1 80 A9
   Total packet length =   39. [Encrypted]
              DE 97 DF 3B  8C BD 6D 8E  50 30 DA 4C  63 B7 8B 49
              67 B1 9E DB  B7 33 CD 11  14 F6 4E B2  26 08 93 68
              C3 54 82 8D  95 0C C5
Top   ToC   RFC5528 - Page 16
   =============== Packet Vector #17 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 60 CF F1  A3 1E A1 B1  60 B6 A3 1C  1C
   Total packet length =   32. [Input (12 cleartext header octets)]
              A5 EE 93 E4  57 DF 05 46  6E 78 2D CF  2E 20 21 12
              98 10 5F 12  9D 5E D9 5B  93 F7 2D 30  B2 FA CC D7
   CBC IV in: 59 00 60 CF  F1 A3 1E A1  B1 60 B6 A3  1C 1C 00 14
   CBC IV out:C3 34 69 7D  11 38 73 06  BD 34 E2 10  1F 66 17 E8
   After xor: C3 38 CC 93  82 DC 24 D9  B8 72 8C 68  32 A9 17 E8   [hdr]
   After CAM: 43 6F 37 74  AB 94 3B 41  EA AD 00 CA  C3 99 13 7B
   After xor: 6D 4F 16 66  33 84 64 53  77 F3 D9 91  50 6E 3E 4B   [msg]
   After CAM: 2D 28 FB 62  DA 06 97 A7  4C D4 31 B8  B5 AE AE EE
   After xor: 9F D2 37 B5  DA 06 97 A7  4C D4 31 B8  B5 AE AE EE   [msg]
   After CAM: F3 DE 10 CD  91 4D B1 B6  CC 37 F0 A2  4A 5A B7 A1
   MIC tag  : F3 DE 10 CD  91 4D B1 B6
   CTR Start: 01 00 60 CF  F1 A3 1E A1  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: 25 E6 9A F0  30 A9 56 E6  FF C0 3F 87  87 7A 89 74
   CTR[0002]: A2 1B 46 23  76 A2 1E DD  F2 AC 4B EC  42 95 3D D3
   CTR[MIC ]: C2 99 28 FF  E7 BB DB 29
   Total packet length =   40. [Encrypted]
              A5 EE 93 E4  57 DF 05 46  6E 78 2D CF  0B C6 BB E2
              A8 B9 09 F4  62 9E E6 DC  14 8D A4 44  10 E1 8A F4
              31 47 38 32  76 F6 6A 9F

   =============== Packet Vector #18 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 0F 85 CD  99 5C 97 B1  60 B6 A3 1C  1C
   Total packet length =   33. [Input (12 cleartext header octets)]
              24 AA 1B F9  A5 CD 87 61  82 A2 50 74  26 45 94 1E
              75 63 2D 34  91 AF 0F C0  C9 87 6C 3B  E4 AA 74 68
              C9
   CBC IV in: 59 00 0F 85  CD 99 5C 97  B1 60 B6 A3  1C 1C 00 15
   CBC IV out:72 0A 46 75  0F 40 59 53  F2 3B D2 1F  6A 11 60 F6
   After xor: 72 06 62 DF  14 B9 FC 9E  75 5A 50 BD  3A 65 60 F6   [hdr]
   After CAM: 67 73 A0 FD  D5 7E D3 5E  E8 24 06 D0  A1 8B 0E 18
   After xor: 41 36 34 E3  A0 1D FE 6A  79 8B 09 10  68 0C 62 23   [msg]
   After CAM: BB 1E D8 9F  60 29 D0 99  09 14 06 A5  E3 8B 72 7B
   After xor: 5F B4 AC F7  A9 29 D0 99  09 14 06 A5  E3 8B 72 7B   [msg]
   After CAM: 3E 4F 40 73  D1 31 E9 B8  02 C8 99 BC  FD AC 19 4B
   MIC tag  : 3E 4F 40 73  D1 31 E9 B8
   CTR Start: 01 00 0F 85  CD 99 5C 97  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: 04 6F 42 2C  8F 52 FB 9B  06 A3 3B 9F  B7 F0 A6 00
   CTR[0002]: 34 76 51 DB  89 10 FB E6  73 E8 56 6E  DB 66 47 5D
   CTR[MIC ]: 9F EC 93 6C  5C 7A AD 0F
   Total packet length =   41. [Encrypted]
              24 AA 1B F9  A5 CD 87 61  82 A2 50 74  22 2A D6 32
              FA 31 D6 AF  97 0C 34 5F  7E 77 CA 3B  D0 DC 25 B3
              40 A1 A3 D3  1F 8D 4B 44  B7
Top   ToC   RFC5528 - Page 17
   =============== Packet Vector #19 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 C2 9B 2C  AA C4 CD B1  60 B6 A3 1C  1C
   Total packet length =   31. [Input (8 cleartext header octets)]
              69 19 46 B9  CA 07 BE 87  07 01 35 A6  43 7C 9D B1
              20 CD 61 D8  F6 C3 9C 3E  A1 25 FD 95  A0 D2 3D
   CBC IV in: 61 00 C2 9B  2C AA C4 CD  B1 60 B6 A3  1C 1C 00 17
   CBC IV out:74 AD F8 04  05 2A 48 E7  46 97 38 D5  BA A1 27 79
   After xor: 74 A5 91 1D  43 93 82 E0  F8 10 38 D5  BA A1 27 79   [hdr]
   After CAM: BD C3 B1 41  1C 64 C8 B3  A9 DC 6A 94  78 97 88 E2
   After xor: BA C2 84 E7  5F 18 55 02  89 11 0B 4C  8E 54 14 DC   [msg]
   After CAM: 7D 6C 8A BF  AD 68 48 D8  C5 FB CD 1E  AF F2 44 99
   After xor: DC 49 77 2A  0D BA 75 D8  C5 FB CD 1E  AF F2 44 99   [msg]
   After CAM: 19 99 AB 92  5E 30 46 96  3D EF FB 1B  4C 87 F7 76
   MIC tag  : 19 99 AB 92  5E 30 46 96  3D EF
   CTR Start: 01 00 C2 9B  2C AA C4 CD  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: 02 B9 D4 1F  87 E0 60 E7  EF DE 6B 7E  D3 DE 5E D2
   CTR[0002]: 61 49 31 C5  2F 34 AA 47  A3 E4 D3 2C  0B 36 41 C6
   CTR[MIC ]: B9 9F C6 C5  96 7B AA 8E  1A 87
   Total packet length =   41. [Encrypted]
              69 19 46 B9  CA 07 BE 87  05 B8 E1 B9  C4 9C FD 56
              CF 13 0A A6  25 1D C2 EC  C0 6C CC 50  8F E6 97 A0
              06 6D 57 C8  4B EC 18 27  68

   =============== Packet Vector #20 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 2C 6B 75  95 EE 62 B1  60 B6 A3 1C  1C
   Total packet length =   32. [Input (8 cleartext header octets)]
              D0 C5 4E CB  84 62 7D C4  C8 C0 88 0E  6C 63 6E 20
              09 3D D6 59  42 17 D2 E1  88 77 DB 26  4E 71 A5 CC
   CBC IV in: 61 00 2C 6B  75 95 EE 62  B1 60 B6 A3  1C 1C 00 18
   CBC IV out:35 A9 48 70  F9 B0 C7 85  FB 32 1A D1  3C 8C A4 9A
   After xor: 35 A1 98 B5  B7 7B 43 E7  86 F6 1A D1  3C 8C A4 9A   [hdr]
   After CAM: 0A 3C E3 0F  AC 09 DC 5C  00 10 5C 69  AC 19 F7 19
   After xor: C2 FC 6B 01  C0 6A B2 7C  09 2D 8A 30  EE 0E 25 F8   [msg]
   After CAM: 61 CD 80 D0  72 E6 84 E1  BF E1 4A 00  27 2A 4D 96
   After xor: E9 BA 5B F6  3C 97 21 2D  BF E1 4A 00  27 2A 4D 96   [msg]
   After CAM: E5 F9 F2 AB  47 FD 7B 8D  6F 72 F4 72  74 D7 69 BB
   MIC tag  : E5 F9 F2 AB  47 FD 7B 8D  6F 72
   CTR Start: 01 00 2C 6B  75 95 EE 62  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: 9C 0E 31 66  B2 81 58 31  5E 63 16 5A  9D BD CE 35
   CTR[0002]: 00 3E 66 D3  E0 5F 7E A7  EF C8 9A 5F  DD 39 E3 54
   CTR[MIC ]: 9A 5E 87 1A  17 10 38 0E  AA DB
   Total packet length =   42. [Encrypted]
              D0 C5 4E CB  84 62 7D C4  54 CE B9 68  DE E2 36 11
              57 5E C0 03  DF AA 1C D4  88 49 BD F5  AE 2E DB 6B
              7F A7 75 B1  50 ED 43 83  C5 A9
Top   ToC   RFC5528 - Page 18
   =============== Packet Vector #21 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 C5 3C D4  C2 AA 24 B1  60 B6 A3 1C  1C
   Total packet length =   33. [Input (8 cleartext header octets)]
              E2 85 E0 E4  80 8C DA 3D  F7 5D AA 07  10 C4 E6 42
              97 79 4D C2  B7 D2 A2 07  57 B1 AA 4E  44 80 02 FF
              AB
   CBC IV in: 61 00 C5 3C  D4 C2 AA 24  B1 60 B6 A3  1C 1C 00 19
   CBC IV out:2A 3C 23 B2  43 F5 1C 35  F7 79 5A CB  3B 20 21 2F
   After xor: 2A 34 C1 37  A3 11 9C B9  2D 44 5A CB  3B 20 21 2F   [hdr]
   After CAM: A1 7E AD 4C  EE AB 51 21  1D 2A 32 F2  D4 45 A6 D6
   After xor: 56 23 07 4B  FE 6F B7 63  8A 53 7F 30  63 97 04 D1   [msg]
   After CAM: A9 A1 32 55  8F C6 9B 98  A9 CC 23 96  FE CA 84 EB
   After xor: FE 10 98 1B  CB 46 99 67  02 CC 23 96  FE CA 84 EB   [msg]
   After CAM: 6A 5E 04 42  D1 A5 7E 17  9A 6C 8B 56  F7 19 80 C5
   MIC tag  : 6A 5E 04 42  D1 A5 7E 17  9A 6C
   CTR Start: 01 00 C5 3C  D4 C2 AA 24  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: 46 1D EF 41  AF A2 94 52  5D 51 AE CB  04 49 74 CD
   CTR[0002]: 29 2E 62 66  1B 66 9A 2B  97 72 6B 77  32 A8 DC 35
   CTR[MIC ]: B8 54 06 A2  6C 6F 93 37  8A BF
   Total packet length =   43. [Encrypted]
              E2 85 E0 E4  80 8C DA 3D  B1 40 45 46  BF 66 72 10
              CA 28 E3 09  B3 9B D6 CA  7E 9F C8 28  5F E6 98 D4
              3C D2 0A 02  E0 BD CA ED  20 10 D3

   =============== Packet Vector #22 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 BE E9 26  7F BA DC B1  60 B6 A3 1C  1C
   Total packet length =   31. [Input (12 cleartext header octets)]
              6C AE F9 94  11 41 57 0D  7C 81 34 05  C2 38 82 2F
              AC 5F 98 FF  92 94 05 B0  AD 12 7A 4E  41 85 4E
   CBC IV in: 61 00 BE E9  26 7F BA DC  B1 60 B6 A3  1C 1C 00 13
   CBC IV out:20 60 6A D1  E1 A0 84 52  2F A3 8B F4  88 1D D6 8B
   After xor: 20 6C 06 7F  18 34 95 13  78 AE F7 75  BC 18 D6 8B   [hdr]
   After CAM: 71 FD FF E7  D9 C8 95 75  D3 EC 0B 7E  7B 8B BE E7
   After xor: B3 C5 7D C8  75 97 0D 8A  41 78 0E CE  D6 99 C4 A9   [msg]
   After CAM: CA AD 93 9C  59 BA 40 AA  1A 0B 88 1B  EE 3D 3C 65
   After xor: 8B 28 DD 9C  59 BA 40 AA  1A 0B 88 1B  EE 3D 3C 65   [msg]
   After CAM: DC 48 8F AA  9C 75 E7 03  17 56 C2 C7  48 48 8D 1B
   MIC tag  : DC 48 8F AA  9C 75 E7 03  17 56
   CTR Start: 01 00 BE E9  26 7F BA DC  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: 56 F0 17 B3  BD 09 02 D6  EA A5 A2 91  AD 4A 2D E5
   CTR[0002]: 20 3D 34 21  EF 5B F8 FC  7B 21 5C 76  7B A5 21 A6
   CTR[MIC ]: F1 A2 86 9C  2A 9E B8 61  48 0B
   Total packet length =   41. [Encrypted]
              6C AE F9 94  11 41 57 0D  7C 81 34 05  94 C8 95 9C
              11 56 9A 29  78 31 A7 21  00 58 57 AB  61 B8 7A 2D
              EA 09 36 B6  EB 5F 62 5F  5D
Top   ToC   RFC5528 - Page 19
   =============== Packet Vector #23 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 DF A8 B1  24 50 07 B1  60 B6 A3 1C  1C
   Total packet length =   32. [Input (12 cleartext header octets)]
              36 A5 2C F1  6B 19 A2 03  7A B7 01 1E  4D BF 3E 77
              4A D2 45 E5  D5 89 1F 9D  1C 32 A0 AE  02 2C 85 D7
   CBC IV in: 61 00 DF A8  B1 24 50 07  B1 60 B6 A3  1C 1C 00 14
   CBC IV out:78 FD B6 AF  61 9E 1C 8D  82 41 17 A8  73 60 1B 70
   After xor: 78 F1 80 0A  4D 6F 77 94  20 42 6D 1F  72 7E 1B 70   [hdr]
   After CAM: 62 2E 28 65  92 43 DB 82  88 79 09 1E  A7 24 54 67
   After xor: 2F 91 16 12  D8 91 9E 67  5D F0 16 83  BB 16 F4 C9   [msg]
   After CAM: 95 0E 52 08  FF 16 70 8C  1E D9 BB 06  3E 1E 41 CF
   After xor: 97 22 D7 DF  FF 16 70 8C  1E D9 BB 06  3E 1E 41 CF   [msg]
   After CAM: BA CD 51 FC  77 F4 02 8D  47 D5 7D 54  7D 46 33 4B
   MIC tag  : BA CD 51 FC  77 F4 02 8D  47 D5
   CTR Start: 01 00 DF A8  B1 24 50 07  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: 15 D6 DD DD  98 96 39 91  35 75 1A 64  B8 D8 D4 F9
   CTR[0002]: 7D 61 6D 1D  EB 92 00 2B  6F FA AB 53  BC AF 69 89
   CTR[MIC ]: 33 E9 27 BE  E1 59 06 9C  DB 32
   Total packet length =   42. [Encrypted]
              36 A5 2C F1  6B 19 A2 03  7A B7 01 1E  58 69 E3 AA
              D2 44 7C 74  E0 FC 05 F9  A4 EA 74 57  7F 4D E8 CA
              89 24 76 42  96 AD 04 11  9C E7

   =============== Packet Vector #24 ==================
   CAM Key:   D7 5C 27 78  07 8C A9 3D  97 1F 96 FD  E7 20 F4 CD
   Nonce =    00 3B 8F D8  D3 A9 37 B1  60 B6 A3 1C  1C
   Total packet length =   33. [Input (12 cleartext header octets)]
              A4 D4 99 F7  84 19 72 8C  19 17 8B 0C  9D C9 ED AE
              2F F5 DF 86  36 E8 C6 DE  0E ED 55 F7  86 7E 33 33
              7D
   CBC IV in: 61 00 3B 8F  D8 D3 A9 37  B1 60 B6 A3  1C 1C 00 15
   CBC IV out:84 E6 CF DD  6A 37 68 5D  E6 71 AD 54  B3 BE FE B9
   After xor: 84 EA 6B 09  F3 C0 EC 44  94 FD B4 43  38 B2 FE B9   [hdr]
   After CAM: C5 0F A0 62  20 18 F1 21  0E BC 3D 2E  47 B7 B8 C3
   After xor: 58 C6 4D CC  0F ED 2E A7  38 54 FB F0  49 5A ED 34   [msg]
   After CAM: C4 6F 6D C3  17 3C 2A 7A  81 FC 2D DA  7F B7 C6 60
   After xor: 42 11 5E F0  6A 3C 2A 7A  81 FC 2D DA  7F B7 C6 60   [msg]
   After CAM: DF AB 2E 76  B0 67 50 B3  7C DD 9A AC  F3 79 17 71
   MIC tag  : DF AB 2E 76  B0 67 50 B3  7C DD
   CTR Start: 01 00 3B 8F  D8 D3 A9 37  B1 60 B6 A3  1C 1C 00 01
   CTR[0001]: D6 D0 6C F8  16 CE D0 F1  A0 E0 AC 71  BA B9 AD 34
   CTR[0002]: 76 4A FF 9A  1B F8 55 1F  68 54 39 0A  EE 37 24 28
   CTR[MIC ]: 4B F4 31 B8  17 86 4B 5D  16 F2
   Total packet length =   43. [Encrypted]
              A4 D4 99 F7  84 19 72 8C  19 17 8B 0C  4B 19 81 56
              39 3B 0F 77  96 08 6A AF  B4 54 F8 C3  F0 34 CC A9
              66 94 5F 1F  CE A7 E1 1B  EE 6A 2F
Top   ToC   RFC5528 - Page 20

5. Security Considerations

Camellia-CTR and Camellia-CCM employ CTR mode for confidentiality. For the security of CTR mode, refer to the Security Considerations of [16].

6. Acknowledgments

Thanks to Rui Hodai for comments and suggestions. Special thanks to Alfred Hoenes for several very detailed reviews and suggestions.

7. References

7.1. Normative References

[1] Matsui, M., Nakajima, J., and S. Moriai, "A Description of the Camellia Encryption Algorithm", RFC 3713, April 2004. [2] Bradner, S., "Key words for use in RFCs to Indicate Requirement Levels", BCP 14, RFC 2119, March 1997. [3] Dworkin, M., "Recommendation for Block Cipher Modes of Operation - Methods and Techniques", NIST Special Publication 800-38A, December 2001, <http://csrc.nist.gov/ publications/nistpubs/800-38a/sp800-38a.pdf>. [4] National Institute of Standards and Technology, "Recommendation for Block Cipher Modes Operation : The CCM Mode for Authentication and Confidentiality", May 2004, <http:// csrc.nist.gov/publications/nistpubs/800-38C/SP800-38C.pdf>.

7.2. Informative References

[5] National Institute of Standards and Technology, "Advanced Encryption Standard (AES)", FIPS PUB 197, November 2001, <http://csrc.nist.gov/publications/fips/fips197/fips-197.pdf>. [6] Kato, A., Moriai, S., and M. Kanda, "The Camellia Cipher Algorithm and Its Use With IPsec", RFC 4312, December 2005. [7] Moriai, S., Kato, A., and M. Kanda, "Addition of Camellia Cipher Suites to Transport Layer Security (TLS)", RFC 4132, July 2005. [8] Moriai, S. and A. Kato, "Use of the Camellia Encryption Algorithm in Cryptographic Message Syntax (CMS)", RFC 3657, January 2004.
Top   ToC   RFC5528 - Page 21
   [9]   Eastlake, D., "Additional XML Security Uniform Resource
         Identifiers (URIs)", RFC 4051, April 2005.

   [10]  International Organization for Standardization, "Information
         technology - Security techniques - Encryption algorithms - Part
         3: Block ciphers", ISO/IEC 18033-3, July 2005.

   [11]  "The NESSIE project (New European Schemes for Signatures,
         Integrity and Encryption)",
         <http://www.cosic.esat.kuleuven.be/nessie/>.

   [12]  Information-technology Promotion Agency (IPA), "Cryptography
         Research and Evaluation Committees",
         <http://www.ipa.go.jp/security/enc/CRYPTREC/index-e.html>.

   [13]  "Camellia open source software",
         <http://info.isl.ntt.co.jp/crypt/eng/camellia/source.html>.

   [14]  "Camellia web site", <http://info.isl.ntt.co.jp/camellia/>.

   [15]  Whiting, D., Housley, R., and N. Ferguson, "Counter with CBC-
         MAC (CCM)", RFC 3610, September 2003.

   [16]  Housley, R., "Using Advanced Encryption Standard (AES) Counter
         Mode With IPsec Encapsulating Security Payload (ESP)",
         RFC 3686, January 2004.
Top   ToC   RFC5528 - Page 22

Authors' Addresses

Akihiro Kato NTT Software Corporation Phone: +81-45-212-7577 Fax: +81-45-212-9800 EMail: akato@po.ntts.co.jp Masayuki Kanda NTT Phone: +81-422-59-3456 Fax: +81-422-59-4015 EMail: kanda.masayuki@lab.ntt.co.jp Satoru Kanno NTT Software Corporation Phone: +81-45-212-7577 Fax: +81-45-212-9800 EMail: kanno-s@po.ntts.co.jp